C# Program to swap numbers without third variable

by Online Tutorials Library July 14, 2022

C# Program to swap two numbers without third variable

We can swap two numbers without using third variable. There are two common ways to swap two numbers without using third variable:

By + and –
By * and /

Program 1: Using ∗ and /

Let’s see a simple C# example to swap two numbers without using third variable.

 using System;   public class SwapExample    {      public static void Main(string[] args)       {        int  a=5, b=10;                  Console.WriteLine(“Before swap a= “+a+” b= “+b);          a=a*b; //a=50 (5*10)            b=a/b; //b=5 (50/10)            a=a/b; //a=10 (50/5)          Console.Write(“After swap a= “+a+” b= “+b);           }   } 

Output:

Before swap a= 5 b= 10      After swap a= 10 b= 5

Program 2: Using + and –

Let’s see another example to swap two numbers using + and -.

 using System;   public class SwapExample    {      public static void Main(string[] args)       {        int  a=5, b=10;                  Console.WriteLine(“Before swap a= “+a+” b= “+b);          a=a+b; //a=15 (5+10)            b=a-b; //b=5 (15-10)            a=a-b; //a=10 (15-5)         Console.Write(“After swap a= “+a+” b= “+b);            }   } 

Output:

Before swap a= 5 b= 10      After swap a= 10 b= 5

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C# Program to swap numbers without third variable

C# Program to swap two numbers without third variable

Program 1: Using ∗ and /

Program 2: Using + and –

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