Program to convert infix to postfix expression in C++ using the Stack Data Structure

Infix expression

An infix expression is an expression in which operators (+, -, *, /) are written between the two operands. For example, consider the following expressions:

Here we have written ‘+’ operator between the operands A and B, and the – operator in between the C and D operand.

Postfix Expression

The postfix operator also contains operator and operands. In the postfix expression, the operator is written after the operand. It is also known as Reverse Polish Notation. For example, consider the following expressions:

Algorithm to Convert Infix to Postfix Expression Using Stack

Following is the algorithm to convert infix expression into Reverse Polish notation.

Initialize the Stack.
Scan the operator from left to right in the infix expression.
If the leftmost character is an operand, set it as the current output to the Postfix string.
And if the scanned character is the operator and the Stack is empty or contains the ‘(‘, ‘)’ symbol, push the operator into the Stack.
If the scanned operator has higher precedence than the existing precedence operator in the Stack or if the Stack is empty, put it on the Stack.
If the scanned operator has lower precedence than the existing operator in the Stack, pop all the Stack operators. After that, push the scanned operator into the Stack.
If the scanned character is a left bracket ‘(‘, push it into the Stack.
If we encountered right bracket ‘)’, pop the Stack and print all output string character until ‘(‘ is encountered and discard both the bracket.
Repeat all steps from 2 to 8 until the infix expression is scanned.
Print the Stack output.
Pop and output all characters, including the operator, from the Stack until it is not empty.

Let’s translate an infix expression into postfix expression in the stack:

Here, we have infix expression (( A * (B + D)/E) – F * (G + H / K))) to convert into its equivalent postfix expression:

Label No.	Symbol Scanned	Stack	Expression
1	(	(
2	(	((
3	A	((	A
4	*	((*	A
5	(	((*(	A
6	B	((*(	AB
7	+	((*(+	AB
8	D	((*(+	ABD
9	)	((*	ABD+
10	/	((*/	ABD+
11	E	((*/	ABD+E
12	)	(	ABD+E/*
13	–	(-	ABD+E/*
14	(	(-(	ABD+E/*
15	F	(-(	ABD+E/*F
16	*	(-(*	ABD+E/*F
17	(	(-(*(	ABD+E/*F
18	G	(-(*(	ABD+E/*FG
19	+	(-(*(+	ABD+E/*FG
20	H	(-(*(+	ABD+E/*FGH
21	/	(-(*(+/	ABD+E/*FGH
22	K	(-(*(+/	ABD+E/*FGHK
23	)	(-(*	ABD+E/*FGHK/+
24	)	(-	ABD+E/FGHK/+
25	)		ABD+E/FGHK/+-

Program to convert infix expression to postfix expression

Let’s create a C++ program that converts infix expression to the postfix expression

  #include<iostream>  #include<stack>  using namespace std;  // defines the Boolean function for operator, operand, equalOrhigher precedence and the string conversion function.  bool IsOperator(char);  bool IsOperand(char);  bool eqlOrhigher(char, char);  string convert(string);    int main()  {  string infix_expression, postfix_expression;  int ch;  do  {  cout << ” Enter an infix expression: “;  cin >> infix_expression;   postfix_expression = convert(infix_expression);   cout << “n Your Infix expression is: ” << infix_expression;  cout << “n Postfix expression is: ” << postfix_expression;  cout << “n t Do you want to enter infix expression (1/ 0)?”;  cin >> ch;  //cin.ignore();   } while(ch == 1);  return 0;  }    // define the IsOperator() function to validate whether any symbol is operator.  /* If the symbol is operator, it returns true, otherwise false. */  bool IsOperator(char c)  {  if(c == ‘+’ || c == ‘-‘ || c == ‘*’ || c == ‘/’ || c == ‘^’ )  return true;     return false;  }    // IsOperand() function is used to validate whether the character is operand.  bool IsOperand(char c)  {  if( c >= ‘A’ && c <= ‘Z’)  /* Define the character in between A to Z. If not, it returns False.*/  return true;  if (c >= ‘a’ && c <= ‘z’)  // Define the character in between a to z. If not, it returns False. */  return true;  if(c >= ‘0’ && c <= ‘9’)   // Define the character in between 0 to 9. If not, it returns False. */  return true;  return false;  }  // here, precedence() function is used to define the precedence to the operator.  int precedence(char op)  {  if(op == ‘+’ || op == ‘-‘)                   /* it defines the lowest precedence */  return 1;  if (op == ‘*’ || op == ‘/’)  return 2;  if(op == ‘^’)                                  /* exponent operator has the highest precedence *  return 3;        return 0;  }  /* The eqlOrhigher() function is used to check the higher or equal precedence of the two operators in infix expression. */  bool eqlOrhigher (char op1, char op2)  {  int p1 = precedence(op1);  int p2 = precedence(op2);  if (p1 == p2)  {  if (op1 == ‘^’ )  return false;  return true;  }  return  (p1>p2 ? true : false);  }    /* string convert() function is used to convert the infix expression to the postfix expression of the Stack */  string convert(string infix)  {  stack <char> S;  string postfix =””;    char ch;    S.push( ‘(‘ );  infix += ‘)’;    for(int i = 0; i<infix.length(); i++)  {  ch = infix[i];    if(ch == ‘ ‘)  continue;  else if(ch == ‘(‘)  S.push(ch);  else if(IsOperand(ch))  postfix += ch;  else if(IsOperator(ch))  {  while(!S.empty() && eqlOrhigher(S.top(), ch))  {  postfix += S.top();  S.pop();  }  S.push(ch);  }  else if(ch == ‘)’)  {  while(!S.empty() && S.top() != ‘(‘)  {  postfix += S.top();  S.pop();  }  S.pop();  }  }  return postfix;  }  

Output:

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Program to convert infix to postfix expression in C++ using the Stack Data Structure

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