Strong number in C

by Online Tutorials Library July 14, 2022

Strong number in C

A number can be said as a strong number when the sum of the factorial of the individual digits is equal to the number.

For example, 145 is a strong number.

Let’s understand through an example.

Program to check whether the number is strong or not.

  #include <stdio.h>  int main()  {      int n;      int sum=0;      printf(“Enter a number”);      scanf(“%d”,&n);      int k=n;      int r;      while(k!=0)      {          r=k%10;          int f=fact(r);          k=k/10;          sum=sum+f;      }      if(sum==n)      {          printf(“nNumber is a strong”);      }      else      {          printf(“nNumber is not a strong”);      }      return 0;  }  int fact(int r)  {      int mul=1;      for(int i=1;i<=r;i++)      {          mul=mul*i;      }      return mul;        }  

In the above code, the input data is retrieved from the user, and then the data is checked whether the input data is a strong number or not.

Output

Program to print the strong numbers from 1 to n.

  #include<stdio.h>  int main()  {      int fact=1,sum=0;      int n,r;      printf(“Enter the ‘n’ number”);      scanf(“%d”,&n);      printf(“n Strong numbers are :”);      for(int i=1;i<=n;i++)      {          int k=i;          while(k!=0)          {              r=k%10;              fact=factorial(r);                                     k=k/10;              sum=sum+fact;          }          if(sum==i){          printf(“%d, “,i);                       }             sum=0;      }                 return 0;  }     int factorial(int f)      {          int mul=1;          for(int i=1; i<=f;i++)          {              mul=mul*i;          }          return mul;      }  

Output

Program to find strong numbers in a given range.

  #include<stdio.h>  int main()  {      int fact=1,sum=0;      int n1,n2,r;      printf(“Enter the first number”);      scanf(“%d”,&n1);      printf(“nEnter the last number”);      scanf(“%d”,&n2);      printf(“nStrong numbers are :”);      for(int i=n1;i<=n2;i++)      {          int k=i;          while(k!=0)          {              r=k%10;              fact=factorial(r);              k=k/10;              sum=sum+fact;          }          if(sum==i){          printf(“%d, “,i);          }             sum=0;      }     return 0;  }  int factorial(int f)   {          int mul=1;          for(int i=1; i<=f;i++)          {              mul=mul*i;          }          return mul;      }  

Output:

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