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# Aptitude Calendar Test Paper 1

1) If January 1, 1996, was Monday, what day of the week was January 1, 1997?

- Thursday
- Wednesday
- Friday
- Sunday

The correct option is (B)

**Explanation:**

The year 1996 is divisible by 4, so it is a leap year with 2 odd days.

As per the question, the first day of the year 1996 was Monday, so the first day of the year 1997 must be two days after Monday. So, it was Wednesday.

2) The first republic day of India was celebrated on January 26, 1950. What day of the week was it?

- Wednesday
- Friday
- Thursday
- Tuesday

The correct option is (C)

**Explanation:**

â‡’ 1600 years are divisible by 400, so the year 1600 has 0 odd days.

â‡’ 300 years have 1 odd day.

â‡’ 49 years = (12 leap years + 37 years)

= (12*2, odd days + 37*1, odd days)

= 24 + 37 = 61 odd days

On dividing 61 by 7, we get remainder 5, so 49 years have 5 odd days.

â‡’From January 26, 1950, to January 26, 1950, we have 26 days.

26 days = 3 weeks + 5 odd days

So, total number of odd days = 1 + 5 + 5 = 11 days

â‡’11 days = 1 week + 4 odd days

4 odd days represent Thursday, so it was Thursday on January 26, 1950.

3) On February 5, 1998, it was Thursday. The day of the week on February 5, 1997, was

- Wednesday
- Monday
- Friday
- Sunday

The correct option is (A)

**Explanation:**

1997 was an ordinary year, it had 1 odd day. So, the day on February 5, 1998, would be one day beyond the day on February 5, 1997.

âˆ´ Thursday on February 5, 1998, would be one day beyond the day on February 5, 1997, so the day on February 5, 1997, was Wednesday.

4) Today is Wednesday, after 68 days, it will be

- Friday
- Sunday
- Monday
- Thursday

The correct option is (C)

**Explanation:**

Each day of a week is repeated after 7 days, so after 70 days, it will be Wednesday.

Therefore, after 68 days, it will be Monday.

5) What was the day of the week on June 17, 1991?

- Tuesday
- Wednesday
- Friday
- Monday

The Correct answer; option (D)

**Explanation:**

June 17, 1991 = (1990 years + period from 01.01.1991 to 17.06.91)

â‡’Odd days in 1600 years = 0

â‡’Odd days in the next 300 years = 15 odd days (2 week + 1 odd day) = 1 odd day

90 years have 22 leap years + 68 ordinary years.

â‡’Number of odd days in 90 years = 22*2 + 68*1 = 112 odd days (16 weeks + 0 odd day) = 0 odd day

Number of odd days from 01.01.91 to 17.06.91= Jan. (31) + Feb. (28) + March (31) + April (30) + May (31) + June (17) = 168 days

â‡’168 days = 24 weeks + 0 odd days

Total number of odd days = 0 + 1 + 0+ 0 = 1 odd day

1 odd day represents Monday, so the given day was Monday.