Java ListIterator hasNext() Method with Examples

by Online Tutorials Library July 22, 2022

Java ListIterator hasNext() Method

The hasNext() method of ListIterator interface is used to return true if the given list iterator contains more number of element during traversing the given list in the forward direction.

Syntax

Parameters

Specified by:

hasNext in interface Iterator<E>

Return

The above method is used to return true if the given list iterator contains more number of element during traversing the given list in the forward direction.

Example 1

  import java.util.ArrayList;  import java.util.Iterator;  import java.util.List;  public class JavaListIteratorhasNextExample1 {     public static void main(String[] args) {     List<Long>  li = new ArrayList<>();    Iterator<Long> itr = null;    li.add(66l);    li.add(70l);    li.add(21l);    itr = li.listIterator();    System.out.println(“The final list for long value is given as: “);    while(itr.hasNext()){            System.out.println(itr.next());        }      }  }  

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Output:

The final list for long value is given as:   66  70  21

Example 2

  import java.util.ArrayList;  import java.util.Iterator;  import java.util.List;  public class JavaListIteratorhasNextExample2 {     public static void main(String[] args) {  List<Character>  li = new ArrayList<>();    Iterator<Character> itr = null;    li.add(‘a’);    li.add(‘e’);    li.add(‘i’);    li.add(‘o’);    li.add(‘u’);    itr = li.listIterator();    System.out.println(“The final list for the characters is given as: “);    while(itr.hasNext()){            System.out.println(itr.next());        }      }  }   

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Output:

The final list for the characters is given as:   a  e  i  o  u

Example 3

  import java.util.ArrayList;  import java.util.Iterator;  import java.util.List;  public class JavaListIteratorhasNextExample3 {     public static void main(String[] args) {     List<Integer>  li = new ArrayList<>();    Iterator<Integer> itr = null;    li.add(22);    li.add(44);    li.add(88);    li.add(11);    li.add(33);    itr = li.listIterator();    System.out.println(“The final list for integer value is given as: “);    while(itr.hasNext()){            System.out.println(itr.next());        }      }  }   

Test it Now

Output:

The final list for integer value is given as:   22  44  88  11  33

Next TopicJava ListIterator

Java ListIterator hasNext() Method with Examples

Java ListIterator hasNext() Method

Syntax

Parameters

Specified by:

Return

Example 1

Example 2

Example 3

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