Program to print the average of n numbers

by Online Tutorials Library July 22, 2022

Program to print the average of n numbers

The average is the outcome from the sum of the numbers divided by the count of the numbers being averaged.

For example: 1,2,3,4,5

Number of all elements = 5

Sum of all elements = 1+2+3+4+5 =15

Average = Sum of all elements / number of all elements = 15/5 =3

Average =3

Algorithm

STEP 1: START
STEP 2: DEFINE n.
STEP 3: SET count = 1
STEP 4: DEFINE xF, averageF
STEP 5: SET sumF = 0
STEP 6: ENTER n
STEP 7: REPEAT STEP 8 to 10 UNTIL count<=n
STEP 8: Enter xF
STEP 9: sumF += xF
SETP 10: count = count + 1
SETP 11: SET averageF = sumF/(n-1)
STEP 12: PRINT averageF
STEP 13: END

Java Program

  import static java.lang.Float.sum;  import java.util.Scanner;  public class Average {     public static void main(String[] args)      {        int n, count = 1;         float  xF, averageF, sumF = 0;         Scanner sc = new Scanner(System.in);           System.out.println(“Enter the value of n”);        n = sc.nextInt();        while (count <= n)                {                     System.out.println(“Enter the “+count+” number?”);                    xF = sc.nextInt();                    sumF += xF;                     ++count;                }                     averageF = sumF/n;           System.out.println(“The Average is”+averageF);      }    }  

Output:

Enter the value of n  5  Enter the 1 number?  1  Enter the 2 number?  2    Enter the 3 number?  3  Enter the 4 number?  4  Enter the 5 number?  5  The Average is 3.0

C program

  #include<stdio.h>  void main( )   {     int n, count = 1;     float x, average, sum = 0;     printf(“Enter the value of n?”);    scanf (“%d”,&n);     while (count <= n)        {         printf (“Enter the %d number?”,count);         scanf(“%f”, &x);         sum += x;         ++count;        }         average = sum/n;         printf(“nThe Average is %fn”, average);   }  

Output:

Enter the value of n? 5  Enter the 1 number? 1  Enter the 2 number? 2  Enter the 3 number? 3  Enter the 4 number? 4  Enter the 5 number? 5    The Average is 3.0000

Python program

  n = int(input(“Enter the value of n?”))  sum=0  count = 1  while (count<=n):      x = int(input(“Enter the %d number?”%(count)));      sum = sum + x;      count=count+1;  average  = sum / n;  print(“Average using a while loop “, average)  

Output:

Enter the value of n? 5  Enter the 1 number? 1  Enter the 2 number? 2  Enter the 3 number? 3  Enter the 4 number? 4  Enter the 5 number? 5  Average using a while loop   3.0000

Php program

  <?php  $count=1;  $sum = 0;  $average=0;  echo “Enter the value of n?”;  $n = readline();  while($count<=$n)  {  echo “Enter the number”;  $x = readline();  $sum = $sum+$x;  $count=$count+1;  }  $average=$sum/$n;  echo $average;  ?>  

Output:

Enter the value of n? 5  Enter the number 1  Enter the number 2  Enter the number 3  Enter the number 4  Enter the number 5  3.0000

C# program

  using System;   public class Average  {     public static void Main()      {         int userInput;     int  n, count = 1;         float  x, average, sum = 0;         Console.WriteLine(“Enter the value of n?”);        n=Convert.ToInt32(Console.ReadLine());        while (count <= n)                {                     Console.WriteLine(“Enter the “+count+” number?” );                     userInput = Convert.ToInt32(Console.ReadLine());                    sum += userInput;                     ++count;               }                     average = (float)sum/(n);                     Console.WriteLine(“nThe Average is %fn”);     Console.Write(average);     }}  

Output:

Enter the value of n?  5  Enter the 1 number?  1  Enter the 2 number?  2    Enter the 3 number?  3  Enter the 4 number?  4  Enter the 5 number?  5  The Average is 3.0

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Program to print the average of n numbers

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