Program to print the sum of digits without using modulus

by Online Tutorials Library July 22, 2022

Program to print the sum of digits without using modulus

In this program, we have to add the digits of the entry number without the logic of using modulus(%).

Example:

149: the sum of its digits (1, 4, 9) is 14.

Go through the algorithm to code for this program:

Algorithm

STEP 1: START
STEP 2: ENTER n as a string
STEP 3: SET sum =0
STEP 4: SET i = 0
STEP 4: REPEAT STEP 5 and 6 UNTIL (i<length(n))
STEP 5: sum =sum + n[i]
STEP 6: sum = sum – 48
STEP 7: i = i+1
STEP 7: PRINT sum
STEP 8: END

Java Program

  import java.util.*;  class SumOfDigits {      public static void main(String[] args) {     Scanner sc = new Scanner(System.in);     System.out.println(“Enter the number?”);    String str=sc.nextLine();     char[] n = str.toCharArray();     int sum=0;  for(int i =0;i<n.length;i++)  {     sum = sum + ((int)n[i]);     sum = sum-48;  }  System.out.println(“sum of digits: “+sum);  }     }  

Output:

Enter the number?  345  sum of digits: 12

C Program

  #include <stdio.h>  int main()  {     int c, sum, t;     char n[1000];     printf(“Enter the number?”);     scanf(“%s”, n);     sum = c = 0;     while (n[c] != ‘

Program to print the sum of digits without using modulus

Program to print the sum of digits without using modulus

Algorithm

Java Program

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