Pointer Arithmetic in C

We can perform arithmetic operations on the pointers like addition, subtraction, etc. However, as we know that pointer contains the address, the result of an arithmetic operation performed on the pointer will also be a pointer if the other operand is of type integer. In pointer-from-pointer subtraction, the result will be an integer value. Following arithmetic operations are possible on the pointer in C language:

Increment
Decrement
Addition
Subtraction
Comparison

Incrementing Pointer in C

If we increment a pointer by 1, the pointer will start pointing to the immediate next location. This is somewhat different from the general arithmetic since the value of the pointer will get increased by the size of the data type to which the pointer is pointing.

We can traverse an array by using the increment operation on a pointer which will keep pointing to every element of the array, perform some operation on that, and update itself in a loop.

The Rule to increment the pointer is given below:

Where i is the number by which the pointer get increased.

32-bit

For 32-bit int variable, it will be incremented by 2 bytes.

64-bit

For 64-bit int variable, it will be incremented by 4 bytes.

Let’s see the example of incrementing pointer variable on 64-bit architecture.

  #include  int main(){  int number=50;        int *p;//pointer to int      p=&number;//stores the address of number variable        printf(“Address of p variable is %u n”,p);        p=p+1;        printf(“After increment: Address of p variable is %u n”,p); // in our case, p will get incremented by 4 bytes.      return 0;  }    

Output

Address of p variable is 3214864300   After increment: Address of p variable is 3214864304

Traversing an array by using pointer

  #include<stdio.h>  void main ()  {  int arr[5] = {1, 2, 3, 4, 5};  int *p = arr;  int i;  printf(“printing array elements…n”);  for(i = 0; i< 5; i++)  {  printf(“%d  “,*(p+i));  }  }  

Output

printing array elements...  1  2  3  4  5

Decrementing Pointer in C

Like increment, we can decrement a pointer variable. If we decrement a pointer, it will start pointing to the previous location. The formula of decrementing the pointer is given below:

32-bit

For 32-bit int variable, it will be decremented by 2 bytes.

64-bit

For 64-bit int variable, it will be decremented by 4 bytes.

Let’s see the example of decrementing pointer variable on 64-bit OS.

  #include             void main(){            int number=50;        int *p;//pointer to int      p=&number;//stores the address of number variable        printf(“Address of p variable is %u n”,p);        p=p-1;       printf(“After decrement: Address of p variable is %u n”,p); // P will now point to the immidiate previous location.         }      

Output

Address of p variable is 3214864300   After decrement: Address of p variable is 3214864296

C Pointer Addition

We can add a value to the pointer variable. The formula of adding value to pointer is given below:

32-bit

For 32-bit int variable, it will add 2 * number.

64-bit

For 64-bit int variable, it will add 4 * number.

Let’s see the example of adding value to pointer variable on 64-bit architecture.

  #include  int main(){  int number=50;        int *p;//pointer to int      p=&number;//stores the address of number variable        printf(“Address of p variable is %u n”,p);        p=p+3;   //adding 3 to pointer variable    printf(“After adding 3: Address of p variable is %u n”,p);       return 0;  }    

Output

Address of p variable is 3214864300   After adding 3: Address of p variable is 3214864312

As you can see, the address of p is 3214864300. But after adding 3 with p variable, it is 3214864312, i.e., 4*3=12 increment. Since we are using 64-bit architecture, it increments 12. But if we were using 32-bit architecture, it was incrementing to 6 only, i.e., 2*3=6. As integer value occupies 2-byte memory in 32-bit OS.

C Pointer Subtraction

Like pointer addition, we can subtract a value from the pointer variable. Subtracting any number from a pointer will give an address. The formula of subtracting value from the pointer variable is given below:

32-bit

For 32-bit int variable, it will subtract 2 * number.

64-bit

For 64-bit int variable, it will subtract 4 * number.

Let’s see the example of subtracting value from the pointer variable on 64-bit architecture.

  #include  int main(){  int number=50;        int *p;//pointer to int      p=&number;//stores the address of number variable        printf(“Address of p variable is %u n”,p);        p=p-3; //subtracting 3 from pointer variable    printf(“After subtracting 3: Address of p variable is %u n”,p);        return 0;  }    

Output

Address of p variable is 3214864300   After subtracting 3: Address of p variable is 3214864288

You can see after subtracting 3 from the pointer variable, it is 12 (4*3) less than the previous address value.

However, instead of subtracting a number, we can also subtract an address from another address (pointer). This will result in a number. It will not be a simple arithmetic operation, but it will follow the following rule.

If two pointers are of the same type,

  Address2 – Address1 = (Subtraction of two addresses)/size of data type which pointer points  

Consider the following example to subtract one pointer from an another.

  #include<stdio.h>  void main ()  {  int i = 100;   int *p = &i  int *temp;  temp = p;   p = p + 3;  printf(“Pointer Subtraction: %d – %d = %d”,p, temp, p-temp);  }  

Output

Pointer Subtraction: 1030585080 - 1030585068 = 3

Illegal arithmetic with pointers

There are various operations which can not be performed on pointers. Since, pointer stores address hence we must ignore the operations which may lead to an illegal address, for example, addition, and multiplication. A list of such operations is given below.

Address + Address = illegal
Address * Address = illegal
Address % Address = illegal
Address / Address = illegal
Address & Address = illegal
Address ^ Address = illegal
Address | Address = illegal
~Address = illegal

Pointer to function in C

As we discussed in the previous chapter, a pointer can point to a function in C. However, the declaration of the pointer variable must be the same as the function. Consider the following example to make a pointer pointing to the function.

  #include<stdio.h>  int addition ();  int main ()  {  int result;   int (*ptr)();  ptr = &addition  result = (*ptr)();  printf(“The sum is %d”,result);  }  int addition()  {  int a, b;   printf(“Enter two numbers?”);  scanf(“%d %d”,&a,&b);  return a+b;  }  

Output

Enter two numbers?10 15   The sum is 25

Pointer to Array of functions in C

To understand the concept of an array of functions, we must understand the array of function. Basically, an array of the function is an array which contains the addresses of functions. In other words, the pointer to an array of functions is a pointer pointing to an array which contains the pointers to the functions. Consider the following example.

  #include<stdio.h>  int show();  int showadd(int);  int (*arr[3])();  int (*(*ptr)[3])();    int main ()  {      int result1;  arr[0] = show;  arr[1] = showadd;  ptr = &arr  result1 = (**ptr)();  printf(“printing the value returned by show : %d”,result1);  (*(*ptr+1))(result1);  }  int show()  {  int a = 65;  return a++;  }  int showadd(int b)  {      printf(“nAdding 90 to the value returned by show: %d”,b+90);  }  

Output

printing the value returned by show : 65   Adding 90 to the value returned by show: 155

Next TopicDangling Pointers in C

Pointer Arithmetic in C

Pointer Arithmetic in C

Incrementing Pointer in C

32-bit

64-bit

Traversing an array by using pointer

Decrementing Pointer in C

32-bit

64-bit

C Pointer Addition

32-bit

64-bit

C Pointer Subtraction

32-bit

64-bit

Illegal arithmetic with pointers

Pointer to function in C

Pointer to Array of functions in C

Dangling Pointers in C

Return an Array in C

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